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简单模拟。
#include #include #include #include #include #include #include #include using namespace std;char s[1000];int n;int num,num2,pos;bool f(){ int p=0; for(int i=0;s[i];i++) { if(s[i]>='0'&&s[i]<='9') continue; else if(i==0&&s[i]=='-') continue; else if(s[i]=='.') {p++; continue;} else return 0; } if(p>1) return 0; pos=strlen(s); for(int i=0;s[i];i++) if(s[i]=='.') pos=i; int hh=strlen(s)-pos-1; if(hh>2) return 0; num=0; for(int i=0;i ='0'&&s[i]<='9') num=num*10+s[i]-'0'; if(num>1000) return 0; } if(num>1000) return 0; num2=0; for(int i=pos+1;s[i];i++) num2=num2*10+s[i]-'0'; double a=1.0*num+num2/(pow(10.0,strlen(s)-pos-1)); if(a>1000.0) return 0; return 1;}int main(){ scanf("%d",&n); double sum=0; int geshu=0; for(int i=1;i<=n;i++) { scanf("%s",s); if(f()==0) printf("ERROR: %s is not a legal number\n",s); else { double a=0; a=1.0*num+num2/(pow(10.0,strlen(s)-pos-1)); if(s[0]=='-') a=-a; sum=sum+a; geshu++; } } if(geshu==1) printf("The average of 1 number is %.2lf\n",sum); else if(geshu==0) printf("The average of 0 numbers is Undefined\n"); else printf("The average of %d numbers is %.2lf\n",geshu,sum/geshu); return 0;}
转载于:https://www.cnblogs.com/zufezzt/p/5642702.html